2019 Dec Gold Problem 3 Moortal Cowmbat
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Official Problem Statement[edit]
Problem Statement:
Moortal Cowmbat is a game played on a rectangular grid of size N × M. Each cell of the grid is either empty or contains a single cow. The goal of the game is to move the cows from their initial positions to their final positions.
Solution:
The solution is to use a Breadth-First Search (BFS) algorithm to find the shortest path from the initial position of each cow to its final position. The algorithm works as follows:
1. Start at the initial position of the cow. 2. Check all adjacent cells to see if they are empty. 3. If an empty cell is found, add it to a queue. 4. Repeat steps 2 and 3 until the final position of the cow is reached.
The following C++ code implements the BFS algorithm:
#include <queue> #include <vector> struct Point { int x, y; }; // Returns the shortest path from start to end std::vector<Point> bfs(Point start, Point end, int n, int m) { std::queue<Point> q; q.push(start); std::vector<std::vector<bool>> visited(n, std::vector<bool>(m, false)); visited[start.x][start.y] = true; std::vector<Point> path; while (!q.empty()) { Point curr = q.front(); q.pop(); path.push_back(curr); if (curr == end) { break; } // Check all adjacent cells for (int i = -1; i <= 1; i++) { for (int j = -1; j <= 1; j++) { int x = curr.x + i; int y = curr.y + j; if (x >= 0 && x < n && y >= 0 && y < m && !visited[x][y]) { Point next = {x, y}; q.push(next); visited[x][y] = true; } } } } return path; }