2016 Feb Bronze Problem 3 Load Balancing

Official Problem Statement

Load Balancing

Solution

the input B is not used in this situation. You find every possible x and y coordinates of the fence by adding 1 and minus 1 on each a and b input

Code

import sys

sys.stdin = open("balancing.in", "r") sys.stdout = open("balancing.out", "w")

n,b = map(int,input().split())

x_val = [] y_val = [] x_fen = [] h_fen = []

for _ in range(n): x, y = map(int,input().split()) x_val.append(x) y_val.append(y) x_fen.append(x + 1) h_fen.append(x + 1)

min_balance = n

for v_y in x_fen: for h_x in h_fen:

tl,tr,bl,br = 0,0,0,0 for k in range(n): x,y = x_val[k],y_val[k] if x > h_x and y > v_y: tl+=1 elif x < h_x and y > v_y: tr+=1 elif x > h_x and y < v_y: bl+=1 else: br+=1

min_balance = min(min_balance, max(tl,tr,bl,br))

print(min_balance)