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2016 Dec Gold Problem 1 Moocast
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== Official Problem Statement == [http://www.usaco.org/index.php?page=viewproblem2&cpid=669 Moocast] == Problem == The Moo-cast problem revolves around Farmer John's cows organizing an emergency "moo-cast" system for broadcasting important messages among themselves. The cows equip themselves with walkie-talkies, which have a limited transmission radius. However, cows can relay messages to one another along a path consisting of several hops, eliminating the need for every cow to transmit directly to every other cow. == Solution == Solution: * Utilize depth-first search (DFS) or breadth-first search (BFS) algorithms to explore each cow's broadcast range. For each cow, initiate a DFS or BFS and calculate the number of reachable cows. * For each cow, check whether the distance to other cows is less than or equal to its broadcast radius. If so, the cow can pass the message to the other cow. * Among all cows, find the one that can transmit the message to the largest number of cows. * Output the maximum number of cows. == Code (DFS and Flood Fill) == === C++ === <pre> #include <bits/stdc++.h> using namespace std; struct Cow { int i, x, y; }; vector<Cow> cows; void dfs(unordered_map<int, vector<pair<int, int>>>& graph, vector<bool>& visited, int node, int val) { if (visited[node]) return; visited[node] = true; for (auto edge : graph[node]) { if (visited[edge.first]) continue; if (edge.second <= val) dfs(graph, visited, edge.first, val); } } bool reach(unordered_map<int, vector<pair<int, int>>>& graph, int total, int val) { vector<bool> visited(total, false); dfs(graph, visited, 0, val); return count(visited.begin(), visited.end(), true) >= total; } int main() { freopen("moocast.in", "r", stdin); freopen("moocast.out", "w", stdout); int n; cin >> n; cows.resize(n); for (int i = 0; i < n; i++) { cows[i].i = i; cin >> cows[i].x >> cows[i].y; } int minDistance = 625000000 * 2, maxDistance = 0; unordered_map<int, vector<pair<int, int>>> graph; for (Cow cow : cows) { for (Cow cow1 : cows) { if (cow.i == cow1.i) continue; int d = (cow1.x - cow.x) * (cow1.x - cow.x) + (cow1.y - cow.y) * (cow1.y - cow.y); minDistance = min(d, minDistance); maxDistance = max(d, maxDistance); graph[cow.i].push_back({cow1.i, d}); } } while (minDistance < maxDistance) { int mid = (minDistance + maxDistance) / 2; if (reach(graph, n, mid)) { maxDistance = mid; } else { minDistance = mid + 1; } } cout << maxDistance << endl; } </pre> === Java === <pre> import java.io.*; import java.util.*; public class MooCast { static class Cow { int i, x, y; public Cow(int i, int x, int y) { this.i = i; this.x = x; this.y = y; } } static List<Cow> cows = new ArrayList<>(); public static void dfs(Map<Integer, List<Pair<Integer, Integer>>> graph, boolean[] visited, int node, int val) { if (visited[node]) return; visited[node] = true; for (Pair<Integer, Integer> edge : graph.get(node)) { if (visited[edge.getKey()]) continue; if (edge.getValue() <= val) dfs(graph, visited, edge.getKey(), val); } } public static boolean reach(Map<Integer, List<Pair<Integer, Integer>>> graph, int total, int val) { boolean[] visited = new boolean[total]; dfs(graph, visited, 0, val); int count = 0; for (boolean visit : visited) { if (visit) count++; } return count >= total; } public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new FileReader("moocast.in")); PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("moocast.out"))); int n = Integer.parseInt(br.readLine()); for (int i = 0; i < n; i++) { StringTokenizer st = new StringTokenizer(br.readLine()); int x = Integer.parseInt(st.nextToken()); int y = Integer.parseInt(st.nextToken()); cows.add(new Cow(i, x, y)); } int minDistance = 625000000 * 2, maxDistance = 0; Map<Integer, List<Pair<Integer, Integer>>> graph = new HashMap<>(); for (Cow cow : cows) { for (Cow cow1 : cows) { if (cow.i == cow1.i) continue; int d = (cow1.x - cow.x) * (cow1.x - cow.x) + (cow1.y - cow.y) * (cow1.y - cow.y); minDistance = Math.min(d, minDistance); maxDistance = Math.max(d, maxDistance); graph.computeIfAbsent(cow.i, </pre> === Python === <pre> from collections import defaultdict class Cow: def __init__(self, i, x, y): self.i = i self.x = x self.y = y def dfs(graph, visited, node, val): if visited[node]: return visited[node] = True for edge in graph[node]: if visited[edge[0]]: continue if edge[1] <= val: dfs(graph, visited, edge[0], val) def reach(graph, total, val): visited = [False] * total dfs(graph, visited, 0, val) return sum(visited) >= total def main(): with open('moocast.in', 'r') as fin: n = int(fin.readline().strip()) cows = [Cow(i, *map(int, line.split())) for i, line in enumerate(fin)] min_distance = 625000000 * 2 max_distance = 0 graph = defaultdict(list) for cow in cows: for cow1 in cows: if cow.i == cow1.i: continue d = (cow1.x - cow.x)**2 + (cow1.y - cow.y)**2 min_distance = min(d, min_distance) max_distance = max(d, max_distance) graph[cow.i].append((cow1.i, d)) while min_distance < max_distance: mid = (min_distance + max_distance) // 2 if reach(graph, n, mid): max_distance = mid else: min_distance = mid + 1 with open('moocast.out', 'w') as fout: fout.write(str(max_distance) + '\n') if __name__ == "__main__": main() </pre> == Code (Union Find) == === C++ === <pre> #include <bits/stdc++.h> using namespace std; struct Edge { int i, j, w; bool operator<(const Edge& other) const { return w < other.w; } }; vector<int> parent; int find(int curr) { return parent[curr] == curr ? curr : (parent[curr] = find(parent[curr])); } void merge(int x, int y) { parent[find(x)] = find(y); } int main() { ifstream fin("moocast.in"); ofstream fout("moocast.out"); int n; fin >> n; vector<int> x(n), y(n); for (int i = 0; i < n; i++) { fin >> x[i] >> y[i]; } parent.resize(n); vector<Edge> edges; for (int i = 0; i < n; i++) { parent[i] = i; for (int j = 0; j < i; j++) { int distance = (x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]); edges.push_back({i, j, distance}); } } sort(edges.begin(), edges.end()); int lastWeight = 0; int numComponents = n; for (const Edge& curr : edges) { if (find(curr.i) != find(curr.j)) { merge(curr.i, curr.j); lastWeight = curr.w; if (--numComponents == 1) { break; } } } fout << lastWeight << endl; fout.close(); } </pre> === Java === <pre> import java.io.*; import java.util.*; public class MooCast { static class Edge implements Comparable<Edge> { int i, j, w; public Edge(int i, int j, int w) { this.i = i; this.j = j; this.w = w; } @Override public int compareTo(Edge other) { return this.w - other.w; } } static int[] parent; public static int find(int curr) { return parent[curr] == curr ? curr : (parent[curr] = find(parent[curr])); } public static void merge(int x, int y) { parent[find(x)] = find(y); } public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new FileReader("moocast.in")); PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("moocast.out"))); int n = Integer.parseInt(br.readLine()); int[] x = new int[n]; int[] y = new int[n]; for (int i = 0; i < n; i++) { StringTokenizer st = new StringTokenizer(br.readLine()); x[i] = Integer.parseInt(st.nextToken()); y[i] = Integer.parseInt(st.nextToken()); } parent = new int[n]; ArrayList<Edge> edges = new ArrayList<>(); for (int i = 0; i < n; i++) { parent[i] = i; for (int j = 0; j < i; j++) { int distance = (x[i] - x[j]) * (x[i] - x[j]) + (y[i] - y[j]) * (y[i] - y[j]); edges.add(new Edge(i, j, distance)); } } Collections.sort(edges); int lastWeight = 0; int numComponents = n; for (Edge curr : edges) { if (find(curr.i) != find(curr.j)) { merge(curr.i, curr.j); lastWeight = curr.w; if (--numComponents == 1) { break; } } } pw.println(lastWeight); pw.close(); } } </pre> === Python === <pre> from sys import stdin import heapq def find(curr): global parent return curr if parent[curr] == curr else find(parent[curr]) def merge(x, y): global parent parent[find(x)] = find(y) def main(): with open("moocast.in", "r") as fin: n = int(fin.readline().strip()) coords = [tuple(map(int, fin.readline().split())) for _ in range(n)] parent = list(range(n)) edges = [] for i in range(n): for j in range(i): x1, y1 = coords[i] x2, y2 = coords[j] distance = (x1 - x2) ** 2 + (y1 - y2) ** 2 heapq.heappush(edges, (distance, i, j)) last_weight = 0 num_components = n while num_components > 1: weight, i, j = heapq.heappop(edges) if find(i) != find(j): merge(i, j) last_weight = weight num_components -= 1 with open("moocast.out", "w") as fout: fout.write(str(last_weight) + "\n") if __name__ == "__main__": main() </pre> [[Category:Yearly_2016_2017]] [[Category:Gold]] [[Category:Depth-First Search]] [[Category:Breadth-First Search]] [[Category:Graph]] [[Category:Binary Search]] [[Category:Search]] [[Category:Union Find]] [[Category:Flood Fill]] [[Category:Union-Find]] [[Category:DFS]]
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